There are currently 19 frogs in a (large pond. the frog population grows exponentially, tripling every 8 days. how long will it take (in days for there to be 290 frogs in the pond?
Population growth factor = 3^(days/8) Day zero 19 Frogs Population = 19*3^(days / 8) We are to calculate when population = 290 290 = 19*3^(days / 8) 290 / 19 = 3^(days/8) log(290/19) = (days/8) * log(3) log (15.2631578947) / log (3) = days/8
1.1836443969
/
0.4771212547
= days/8
2.4808041672
= days / 8 days = 8 * 2.4808041672 days =
19.8464333372
days
